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09/22/11 - Existence and Uniqueness of ODE solutions
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  | Problem 2.6.41 (double click on the first page to see the whole problem -- 3 pages)
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  | Problem 2.6.43 (double click on the first page to see the whole problem -- 2 pages)
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  | Problem 2.6.50 (double click on the first page to see the whole problem -- 3 pages)
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 You can't get there from here! No solution exists with given initial condition.
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  | Suppose the function y' = f(x,y) is defined and continuous on the rectangle R in the xy-plane. Then given any point (x0,y0) contained in R, the initial-value problem y' = f(x, y) and y(x0) = y0 has a solution y(x) defined in an interval containing x0. Furthermore, the solution will be defined at least until the solution curve x -> (x, y(x)) leaves the rectangle R.
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 Solution only exists over finite interal!
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  | Can be found from the solution
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  | Is there only one solution that satisfies an initial-value problem? -- Uniqueness of a Solution
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  | Notes on Existence and Uniqueness of Solutions to First-Order ODEs: (double-click on the first page to see the entire document -- 2 pages).
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  | Show that the differential equation
 is exact, and find and graph solutions F(x,y) = C for C = {-3/2, -1, -1/2, 0, 1/2, 1, 3/2, 9/5}. For C = 0, show that there is a value of yo for which there is not a unique solution to the initial-value problem. Explain why there is no unique solution for that value of yo.
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  | Read pp. 77-86 of the text.
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  | Do exercises p. 86 (5,7,13,19).
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